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140=6x^2-2x
We move all terms to the left:
140-(6x^2-2x)=0
We get rid of parentheses
-6x^2+2x+140=0
a = -6; b = 2; c = +140;
Δ = b2-4ac
Δ = 22-4·(-6)·140
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-58}{2*-6}=\frac{-60}{-12} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+58}{2*-6}=\frac{56}{-12} =-4+2/3 $
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